Input total marks and display grade. Grade is calculated as follows.

 Input total marks and display grade. Grade is calculated as follows.

Total Marks	Income Tax
>=360	First class
< 360 but >=270	Second class
< 270 but >=210	Pass class
<210	Fail

#include<stdio.h> #include<conio.h> #include<math.h> void main( ) { int tm; printf("Enter Value of X"); scanf("%d", &tk); if (tm >= 360)   printf("Grade is First Class\n"); else   if (tm >=270)     printf("Grade is Second Class\n");   else       if (tm <= 210)          printf("Grade is Pass Class");       else         printf("Grade is Fail\n"); getch( ); }

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Input Basic Salary. Find and display Income Tax. Income Tax is calculated as follows:

Input Basic Salary. Find and display Income Tax. Income Tax is calculated as follows:

Basic Salary	Income Tax
First 1000	Nil
Next 15	5%
Rest	10%

#include<stdio.h> #include<conio.h> void main( ) { float bs, it; clrscr( ); printf("Enter Basic Salary"); scanf("%f", &bs); if (bs < 1000)   it = 0; else   if (bs < 2500)     it = (bs - 1000)*5/100;   else     it = 75 + (bs - 2500)*10/100; printf("\n Income Tax is = %.2f\n", it); getch( ); }

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Input sales. Find and print commission. Commission is calculated as follows:

 
Input sales. Find and print commission. Commission is calculated as follows:

SALES	Commission
<=10000	1%
>10000 but <=30000	5%
Rest	10%

#include<stdio.h> #include<conio.h> void main( ) { float s, c; clrscr( ); printf("Enter Sales"); scanf("%f", &s); if (s<10000)   c=s*1/100; else   if(s < 30000)     c=s*5/100; else     c=s*10/100; printf("/n Commission is =%.2f", c); getch( ); }

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To input an integer and print whether it is a prime number or not.

Dell D600 Laptop 1.6ghz 40gb DVD/CDRW B Grade Includes Genuine XP Professional restore cd!Write a program in C to input any positive integer and to print whether it is a prime number or not.

#include<stdio.h> #include<conio.h> #include<math.h> void main( ) { int i, m, nd; nd=0; printf("Enter a positive integer\n"); scanf("%d", &m); for(i=1; i<=m; i++) { if(m % i = = 0) nd++; } if(nd ==2) printf("%d is a prime number\n", m); else printf("%d is not a prime number\n",m); }

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Find highest, median and lowest number from the given set of 17 numbers.

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Write a program in C to input 17 observation and then print highest, median and lowest.

#include<stdio.h> #define N 17 void main( ) { int i, j, n[N], t; printf("Enter %d integer values\n", N); for (i=0; i < N; i++) scanf("%d", &n[i]); for(i=0; i < N-1; i++) for (j=i+1; j < N; j++) if (n[i] > n[j]) { t = n[i]; n[i] = n[j]; n[j] = t; } printf("Highest number is %d", n[16]); printf("Median is %d\n", n[8]); printf("Lowest number is %d", n[0]); getch( ); }

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Find the highest and lowest number from the given set of 13 numbers.

Write a program in C to input 13 observation and then print Highest and Lowest.

#include<stdio.h> #define N 13 void main( ) { int i, j, n[N], t; printf("Enter %d integer values\n", N); for (i=0; i < N; i++) scanf("%d", &n[i]); for(i=0; i < N-1; i++) for (j=i+1; j < N; j++) if (n[i] > n[j]) { t = n[i]; n[i] = n[j]; n[j] = t; } printf("Highest number is %d", n[12]); printf("Lowest number is %d", n[0]); getch( ); }

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Input 10 numbers. Find the lowest number from the given set of 10 numbers.

Write a program in C to input 10 observation and then print Lowest.

#include<stdio.h> #define N 10 void main( ) { int i, j, n[N], t; printf("Enter %d integer values\n", N); for (i=0; i < N; i++) scanf("%d", &n[i]); for(i=0; i < N-1; i++) for (j=i+1; j < N; j++) if (n[i] > n[j]) { t = n[i]; n[i] = n[j]; n[j] = t; } printf("Lowest number is %d", n[0]); getch( ); }

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Input 25 numbers. Find the largest number from the given set of 25 numbers.

Write a program in C to input 25 observation and then print Highest.

#include<stdio.h> #define N 25 void main( ) { int i, j, n[N], t; printf("Enter %d integer values\n", N); for (i=0; i < N; i++) scanf("%d", &n[i]); for(i=0; i < N-1; i++) for (j=i+1; j < N; j++) if (n[i] > n[j]) { t = n[i]; n[i] = n[j]; n[j] = t; } printf("Highest number is %d", n[24]); getch( ); }

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Input 15 numbers. Arrange the numbers in ascending order and display the median of the same.

Write a program in C to accept 15 numbers, arrange these numbers in ascending order, display the median of the same.

#include< stdio.h> #define N 15 void main( ) { int i, j, n[N], t; printf("Enter %d integer values\n", N); for (i=0; i < N; i++) scanf("%d", &n[i]); for(i=0; i < N-1; i++) for (j=i+1; j < N; j++) if (n[i] > n[j]) { t = n[i]; n[i] = n[j]; n[j] = t; } printf("Median is %d\n", n[7]); getch( ); }

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Input 20 numbers. Arrange the numbers in ascending order and display ascending order as well as descending order list.

Write a program in C to input 20 integers and then print these integers in ascending order of magnitude and then in descending order of magnitude.

#include<stdio.h> #define N 20 void main( ) { int i, j, n[N], t; printf("Enter %d integer values\n", N); for (i=0; i < N; i++) scanf("%d", &n[i]); for(i=0; i < N-1; i++) for (j=i+1; j < N; j++) if (n[i] > n[j]) { t = n[i]; n[i] = n[j]; n[j] = t; } printf("The ascending order is \n"); for (i=0; i < N; i++) printf("%d\t", n[i]); printf("The descending order is \n"); for (i=N-1; i > = 0; i--) printf("%d", n[i]); getch( ); }

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Input 20 numbers. Arrange the numbers in descending order and display descending order. (Sorting of an array)

Write a program in C accept 20 integers and arrange them in the descending order of values.(Sorting of an array)

#include<stdio.h> #define N 20 void main( ) { int i, j, n[N], t; printf("Enter %d integer values\n", N); for (i=0; i < N; i++) scanf("%d", &n[i]); for(i=0; i < N-1; i++) for (j=i+1; j < N; j++) if (n[i] < n[j]) { t = n[i]; n[i] = n[j]; n[j] = t; } printf("The descending order is \n"); for (i=0; i < N; i++) printf("%d\t", n[i]); getch( ); }

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Input 10 numbers. Arrange the numbers in ascending order and display ascending order. (Sorting of an array)

Write a program in C accept 10 integers and arrange them in the ascending order of values.(Sorting of an array)

#include<stdio.h> #define N 10 void main( ) { int i, j, n[N], t; printf("Enter %d integer values\n", N); for (i=0; i < N; i++) scanf("%d", &n[i]); for(i=0; i < N-1; i++) for (j=i+1; j < N; j++) if (n[i] > n[j]) { t = n[i]; n[i] = n[j]; n[j] = t; } printf("The ascending order is \n"); for (i=0; i < N; i++) printf("%d\t", n[i]); }

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Calculation of depreciation , by using Written Down Value ( WDV ) as well as Straight Line Method ( SLM ).

Enter cost, rate of depreciation and number of years. Display depreciation for each year by WDV method as well as by Straight Line Method.

#include<stdio.h> #include<conio.h> void main( ) { float cost, rate, year, slmdep, wdvdep, cnt; clrscr( ); printf("Enter Cost, Dep.Rate, Years"); scanf("%f %f %f", &cost, &rate, &year); slmdep = cost*rate/100; for (cnt=1; cnt < = year; cnt++) { wdvdep = cost*rate/100; cost = cost - wdvdep; printf("\n Year %f, WDV Dep %.2f, SLM Dep %.2f\n", cnt, wdvdep,slmdep); } getch( ); }

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Calculation of depreciation by using straight Line method ( SLM )

Enter cost, rate of depreciation and number of years. Display depreciation for each year by straight line method.

#include<stdio.h> #include<conio.h> void main( ) { float cost, rate, year, dep, cnt; clrscr( ); printf("Enter Cost, Dep.Rate, Years"); scanf("%f %f %f ", &cost, &rate, &year); dep = cost*rate/100; for(cnt=1; cnt < = year; cnt++) { printf("\n Year %f, Depreciation %.2f\n", cnt, dep); } getch( ); }

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Calculation of depreciation by using WDV method

Enter cost, rate of depreciation and number of years. Display depreciation for each year by WDV method.

#include<stdio.h> #include<conio.h> void main( ) { float cost, rate, year, dep, cnt; clrscr( ); printf("Enter Cost, Dep.Rate, Years"); scanf("%f %f %f", &cost, &rate, &year); for (cnt=1; cnt < = year; cnt++) { dep = cost*rate/100; cost = cost - dep; printf("\n Year %f, Depreciation %.2f\n", cnt, dep); } getch( ); }

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Calculation of depreciation , by using WDV method & scrap value at the end

Write a program in C which will get from the keyboard information about the name of the asset for which depreciation is to be calculated according to diminishing balance method. The operator should also give detail about the cost price of the asset and the rate of depreciation and number of years indicating the life of the asset. The output must show year number (real), value of the asset of that year, depreciation for the year and at end it should indicate the scrap value of the asset.

#include<stdio.h> #include<conio.h> void main( ) { char asset_name[25]; float cost, rate, year, dep, cnt; clrscr( ); printf("Enter Name of asset, cost, Dep, Rate, Life of asset"); scanf("%s %f %f %f", asset_name, &cost, &rate, &year); for (cnt=1; cnt < = year; cnt++) { dep = cost*rate/100; printf("\n Year %.0f, Cost this year %.2f, Depreciation %.2f\n", cnt, cost, dep); cost = cost - dep; } printf("Scrap value %.2f\n", cost); getch( ); }

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Find the GCD of two positive integer.

Find the G.C.D of two positive integer.

#include<stdio.h> #include<conio.h> void main( ) { int a, b; clrscr( ); printf("Enter any two positive integer\n"); scant("%d %d", &a, &b); while (a!=b) { if (a > b) a = a - b; else b = b - a; } printf("The gcd is %d \n", a); }

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Write a program in c ( WAPIC ) to input salesman name and his total sales and print his name, his commission and the additional commission.

A chemical co. offers commission to their salesman at rate of 5% of the total sales amount in order to increase the sales, the company offers an additional commission at 3% of the amount exceeding Rs. 10,000.
Write a prWrite a proogram in c ( WAPIC ) to input salesman name (sn) and his total sales (ts) and print his name, his commission (c) and the additional commission (ac).

#include<stdio.h> void main( ) { char sn[25]; float ts, c, ac; printf("Enter the salesman name and his total sales\n"); scanf("%s %f", sn, &ts); c = ts*0.05; if (ts > 10000) ac = (ts - 10000)*0.03; else ac = 0; printf("Salesman name is %s \n", sn); printf("His commission is Rs %f \n", c); printf("The additional commission is Rs %f \n", ac); }

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Write a program in 'C' to test whether the given integer is even or odd and to print message accordingly.(Using if...........else statement.)

 
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#include<stdio.h> #include<conio.h> #include<math.h> main() { int n; printf("Enter any integer\n"); scanf("%d", &n); if(n % 2 = = 0) printf("The integer %d is even \n", n); else printf("The integer %d is odd \n", n); return(0); }

For eg :-

Output :-
Enter any integer
25
The integer 25 is odd

Output :-
Enter any integer
10
The integer 10 is even

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