SYD Function (Functions in Excel)
Purchase Value Of A New Car | £20,000 | |
Second Hand Value | £8,000 | |
Number Of Years Ownership | 6 | |
Deprecation in year 1 | £3,429 | =SYD(F3,F4,F5,1) |
Deprecation in year 2 | £2,857 | =SYD(F3,F4,F5,2) |
Deprecation in year 3 | £2,286 | =SYD(F3,F4,F5,3) |
Deprecation in year 4 | £1,714 | =SYD(F3,F4,F5,4) |
Deprecation in year 5 | £1,143 | =SYD(F3,F4,F5,5) |
Deprecation in year 6 | £571 | =SYD(F3,F4,F5,6) |
Total Depreciation : | £12,000 | =SUM(F7:F12) |
What Does It Do ? |
This function calculates the depreciation of an item throughout its life, using the sum of the |
years digits. |
The depreciation is greatest in the earlier part of the items life. |
What is the Sum Of The Years Digits ? |
The sum of the years digits adds together the each of the years of the life. |
A life of 3 years has a sum of 1+2+3 equalling 6. |
Each of the years is then calculated as a percentage of the sum of the years. |
Year 3 is 50% of 6, year 2 is 33% of 6, year 1 is 17% 6. |
The total depreciation of the item is then allocated on the basis of these percentages. |
A depreciation of £9000 is allocated as 50% being £4500, 33% being £3000, 17% being £1500. |
£9,000 | ||
1 | 17% | £1,500 |
2 | 33% | £3,000 |
3 | 50% | £4,500 |
As the greater part of the depreciation is allocated to the earliest years the values are |
inverted, year 1 is $4500, year 2 is £3000 and year 1 is £1500. |
Example 1 |
Purchase Price Of A Car : | £10,000 | |||
Salvage Value : | £1,000 | |||
Expected Life in Years : | 3 | |||
As % Of Total Depreciation | ||||
Depreciation in Year 1 : | £4,500 | ===> | 0.5 | |
Depreciation in Year 2 : | £3,000 | ===> | 0.333333 | |
Depreciation in Year 3 : | £1,500 | ===> | 0.166667 | |
=SYD(E39,E40,E41,3) |
1. Add together the digits of the Life to get the SumOfTheYearsDigits, 1+2+3=6. |
2. Subtract the Salvage from the Purchase Price to get Total Deprectation, £10000-£1000=£9000. |
3. Divide the Total Deprectation by the SumOfTheYearsDigits, £9000/6=£1500. |
4. Invert the year digits, 1,2,3 becomes 3,2,1. |
5. Multiply 3,2,1 by £1500 to get £4500, £3000, £1500, these values are the depreciation |
values for each of the three years in the life of the item. |
Example 2 |
The same example using 4 years. |
Purchase Price Of A Car : | £10,000 | |||
Salvage Value : | £1,000 | |||
Expected Life in Years : | 4 | |||
As % Of Total Depriciation | ||||
Depreciation in Year 1 : | £3,600 | 0.4 | ||
Depreciation in Year 2 : | £2,700 | 0.3 | ||
Depreciation in Year 3 : | £1,800 | 0.2 | ||
Depreciation in Year 4 : | £900 | 0.1 | ||
Total Depreciation : | £9,000 | 100% |
Example 3 | |||||||
This example will adjust itself to accommodate any number of years between 1 and 10. | |||||||
Purchase Price Of A Car : | £10,000 | ||||||
Salvage Value : | £1,000 | ||||||
Expected Life in Years (1 to 10) : | 7 | ||||||
As % Of Total Depriciation | |||||||
Year | 1 | £2,250 | 25% | ||||
Year | 2 | £1,929 | 21% | ||||
Year | 3 | £1,607 | 18% | ||||
Year | 4 | £1,286 | 14% | ||||
Year | 5 | £964 | 11% | ||||
Year | 6 | £643 | 7% | ||||
Year | 7 | £321 | 4% | ||||
Year | |||||||
Year | |||||||
Year | |||||||
£9,000 | 100% | ||||||
Syntax | |||||||
=SYD(OriginalCost,SalvageValue,Life,PeriodToCalculate) | |||||||
Formatting | |||||||
No special formatting is needed. |
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