CEILING Function (Functions in Excel)
Number | Raised Up | |
2.1 | 3 | =CEILING(C4,1) |
1.5 | 2 | =CEILING(C5,1) |
1.9 | 2 | =CEILING(C6,1) |
20 | 30 | =CEILING(C7,30) |
25 | 30 | =CEILING(C8,30) |
40 | 60 | =CEILING(C9,30) |
What Does It Do ? |
This function rounds a number up to the nearest multiple specified by the user. |
Syntax |
=CEILING(ValueToRound,MultipleToRoundUpTo) |
The ValueToRound can be a cell address or a calculation. |
Formatting |
No special formatting is needed. |
Example 1 |
The following table was used by a estate agent renting holiday apartments. |
The properties being rented are only available on a weekly basis. |
When the customer supplies the number of days required in the property the =CEILING() |
function rounds it up by a multiple of 7 to calculate the number of full weeks to be billed. |
Days Required | Days To Be Billed | ||
Customer 1 | 3 | 7 | =CEILING(D28,7) |
Customer 2 | 4 | 7 | =CEILING(D29,7) |
Customer 3 | 10 | 14 | =CEILING(D30,7) |
Example 2 |
The following table was used by a builders merchant delivering products to a construction site. |
The merchant needs to hire trucks to move each product. |
Each product needs a particular type of truck of a fixed capacity. |
Table 1 calculates the number of trucks required by dividing the Units To Be Moved by |
the Capacity of the truck. |
This results of the division are not whole numbers, and the builder cannot hire just part |
of a truck. |
Table 1 | ||||
Item | Units To Be Moved | Truck Capacity | Trucks Needed | |
Bricks | 1000 | 300 | 3.33 | =D45/E45 |
Wood | 5000 | 600 | 8.33 | =D46/E46 |
Cement | 2000 | 350 | 5.71 | =D47/E47 |
Table 2 shows how the =CEILING() function has been used to round up the result of |
the division to a whole number, and thus given the exact amount of trucks needed. |
Table 2 | ||||
Item | Units To Be Moved | Truck Capacity | Trucks Needed | |
Bricks | 1000 | 300 | 4 | =CEILING(D54/E54,1) |
Wood | 5000 | 600 | 9 | =CEILING(D55/E55,1) |
Cement | 2000 | 350 | 6 | =CEILING(D56/E56,1) |
Example 3 |
The following tables were used by a shopkeeper to calculate the selling price of an item. |
The shopkeeper buys products by the box. |
The cost of the item is calculated by dividing the Box Cost by the Box Quantity. |
The shopkeeper always wants the price to end in 99 pence. |
Table 1 shows how just a normal division results in varying Item Costs. |
Table 1 | ||||
Item | Box Qnty | Box Cost | Cost Per Item | |
Plugs | 11 | £20 | 1.81818 | =D69/C69 |
Sockets | 7 | £18.25 | 2.60714 | =D70/C70 |
Junctions | 5 | £28.10 | 5.62000 | =D71/C71 |
Adapters | 16 | £28 | 1.75000 | =D72/C72 |
Table 2 shows how the =CEILING() function has been used to raise the Item Cost to always end in 99 pence.
Table 2 | ||||||||
Item | In Box | Box Cost | Cost Per Item | Raised Cost | ||||
Plugs | 11 | £20 | 1.81818 | 1.99 | ||||
Sockets | 7 | £18.25 | 2.60714 | 2.99 | ||||
Junctions | 5 | £28.10 | 5.62000 | 5.99 | ||||
Adapters | 16 | £28 | 1.75000 | 1.99 | ||||
=INT(E83)+CEILING(MOD(E83,1),0.99) | ||||||||
Explanation | ||||||||
=INT(E83) | Calculates the integer part of the price. | |||||||
=MOD(E83,1) | Calculates the decimal part of the price. | |||||||
=CEILING(MOD(E83),0.99) | Raises the decimal to 0.99 | |||||||
0 comments:
Post a Comment